The power of pruning in backtracking III
Interesting problem, you run into TLE if you wait to check the conditions after each permutation is generated. Instead, check as the permutation is being built. Code is down below, cheers, ACC. 2992. Number of Self-Divisible Permutations Medium 3 0 Add to List Share Given an integer n , return the number of permutations of the 1-indexed array nums = [1, 2, ..., n] , such that it's self-divisible . Array nums is self-divisible if for every 1 <= i <= n , at least one of the following conditions holds: nums[i] % i == 0 i % nums[i] == 0 A permutation of an array is a rearrangement of the elements of that array, for example here are all of the permutations of the array [1, 2, 3] : [1, 2, 3] [1, 3, 2] [2, 1, 3] [2, 3, 1] [3, 1, 2] [3, 2, 1] Example 1: Input: n = 1 Output: 1 Explanation: The array [1] has only 1 permutation which is self-divisible. Example 2: Input:...