Standard Priority Queue VI: Max Heap
Although this problem's hint #1 mentions that you should sort the rows, in reality you don't need to. Creating a max heap, adding all elements there, and removing them according to the limits given, should do the trick. Code is down below, cheers, ACC.
Maximum Sum With at Most K Elements - LeetCode
You are given a 2D integer matrix grid
of size n x m
, an integer array limits
of length n
, and an integer k
. The task is to find the maximum sum of at most k
elements from the matrix grid
such that:
The number of elements taken from the
ith
row ofgrid
does not exceedlimits[i]
.
Return the maximum sum.
Example 1:
Input: grid = [[1,2],[3,4]], limits = [1,2], k = 2
Output: 7
Explanation:
- From the second row, we can take at most 2 elements. The elements taken are 4 and 3.
- The maximum possible sum of at most 2 selected elements is
4 + 3 = 7
.
Example 2:
Input: grid = [[5,3,7],[8,2,6]], limits = [2,2], k = 3
Output: 21
Explanation:
- From the first row, we can take at most 2 elements. The element taken is 7.
- From the second row, we can take at most 2 elements. The elements taken are 8 and 6.
- The maximum possible sum of at most 3 selected elements is
7 + 8 + 6 = 21
.
Constraints:
n == grid.length == limits.length
m == grid[i].length
1 <= n, m <= 500
0 <= grid[i][j] <= 105
0 <= limits[i] <= m
0 <= k <= min(n * m, sum(limits))
using System.Collections; public class Solution { public long MaxSum(int[][] grid, int[] limits, int k) { PriorityQueue pQueue = new PriorityQueue(false, grid.Length * grid[0].Length); for (int r = 0; r < grid.Length; r++) for (int c = 0; c < grid[r].Length; c++) pQueue.Enqueue(new QueueItem(grid[r][c], r, c), grid[r][c]); long sum = 0; while (pQueue.Count > 0 && k > 0) { double dVal = 0; QueueItem qi = (QueueItem)pQueue.Dequeue(out dVal); if (limits[qi.indexRow] > 0) { sum += (long)dVal; k--; limits[qi.indexRow]--; } } return sum; } } public class QueueItem { public int value = 0; public int indexRow = 0; public int indexCol = 0; public QueueItem(int value, int indexRow, int indexCol) { this.value = value; this.indexRow = indexRow; this.indexCol = indexCol; } } public class PriorityQueue { public struct HeapEntry { private object item; private double priority; public HeapEntry(object item, double priority) { this.item = item; this.priority = priority; } public object Item { get { return item; } } public double Priority { get { return priority; } } } private bool ascend; private int count; private int capacity; private HeapEntry[] heap; public int Count { get { return this.count; } } public PriorityQueue(bool ascend, int cap = -1) { capacity = 10000000; if (cap > 0) capacity = cap; heap = new HeapEntry[capacity]; this.ascend = ascend; } public object Dequeue(out double priority) { priority = heap[0].Priority; object result = heap[0].Item; count--; trickleDown(0, heap[count]); return result; } public object Peak(out double priority) { priority = heap[0].Priority; object result = heap[0].Item; return result; } public object Peak(/*out double priority*/) { //priority = heap[0].Priority; object result = heap[0].Item; return result; } public void Enqueue(object item, double priority) { count++; bubbleUp(count - 1, new HeapEntry(item, priority)); } private void bubbleUp(int index, HeapEntry he) { int parent = (index - 1) / 2; // note: (index > 0) means there is a parent if (this.ascend) { while ((index > 0) && (heap[parent].Priority > he.Priority)) { heap[index] = heap[parent]; index = parent; parent = (index - 1) / 2; } heap[index] = he; } else { while ((index > 0) && (heap[parent].Priority < he.Priority)) { heap[index] = heap[parent]; index = parent; parent = (index - 1) / 2; } heap[index] = he; } } private void trickleDown(int index, HeapEntry he) { int child = (index * 2) + 1; while (child < count) { if (this.ascend) { if (((child + 1) < count) && (heap[child].Priority > heap[child + 1].Priority)) { child++; } } else { if (((child + 1) < count) && (heap[child].Priority < heap[child + 1].Priority)) { child++; } } heap[index] = heap[child]; index = child; child = (index * 2) + 1; } bubbleUp(index, he); } }
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