Blocks and Long
Long in C# can store numbers up to 9,223,372,036,854,775,807. This problem requires counting the number of blocks in a grid. Not a lot of challenges other than using hashtables and calculations with longs. Code is down below, ACC.
Number of Black Blocks - LeetCode
You are given two integers m and n representing the dimensions of a 0-indexed m x n grid.
You are also given a 0-indexed 2D integer matrix coordinates, where coordinates[i] = [x, y] indicates that the cell with coordinates [x, y] is colored black. All cells in the grid that do not appear in coordinates are white.
A block is defined as a 2 x 2 submatrix of the grid. More formally, a block with cell [x, y] as its top-left corner where 0 <= x < m - 1 and 0 <= y < n - 1 contains the coordinates [x, y], [x + 1, y], [x, y + 1], and [x + 1, y + 1].
Return a 0-indexed integer array arr of size 5 such that arr[i] is the number of blocks that contains exactly i black cells.
Example 1:
Input: m = 3, n = 3, coordinates = [[0,0]] Output: [3,1,0,0,0] Explanation: The grid looks like this:There is only 1 block with one black cell, and it is the block starting with cell [0,0]. The other 3 blocks start with cells [0,1], [1,0] and [1,1]. They all have zero black cells. Thus, we return [3,1,0,0,0].
Example 2:
Input: m = 3, n = 3, coordinates = [[0,0],[1,1],[0,2]] Output: [0,2,2,0,0] Explanation: The grid looks like this:There are 2 blocks with two black cells (the ones starting with cell coordinates [0,0] and [0,1]). The other 2 blocks have starting cell coordinates of [1,0] and [1,1]. They both have 1 black cell. Therefore, we return [0,2,2,0,0].
Constraints:
2 <= m <= 1052 <= n <= 1050 <= coordinates.length <= 104coordinates[i].length == 20 <= coordinates[i][0] < m0 <= coordinates[i][1] < n- It is guaranteed that
coordinatescontains pairwise distinct coordinates.
(There him)
public long[] CountBlackBlocks(int m, int n, int[][] coordinates)
{
Hashtable blocks = new Hashtable();
for (int i = 0; i < coordinates.Length; i++)
{
int r = coordinates[i][0];
int c = coordinates[i][1];
int[] x = { r - 1, r - 1, r, r };
int[] y = { c - 1, c, c - 1, c };
for (int j = 0; j < x.Length; j++)
{
if (x[j] >= 0 &&
x[j] < m &&
y[j] >= 0 &&
y[j] < n &&
x[j] + 1 < m &&
y[j] + 1 < n)
{
long keyBlock = x[j] * (100000 + 7) + y[j];
if (!blocks.ContainsKey(keyBlock)) blocks.Add(keyBlock, 0L);
blocks[keyBlock] = (long)blocks[keyBlock] + 1;
}
}
}
long[] retVal = new long[5];
retVal[0] = 1L * (m - 1) * (n - 1) - blocks.Count;
foreach (long keyBlock in blocks.Keys)
{
long val = (long)blocks[keyBlock];
retVal[val]++;
}
return retVal;
}
There is only 1 block with one black cell, and it is the block starting with cell [0,0].
The other 3 blocks start with cells [0,1], [1,0] and [1,1]. They all have zero black cells.
Thus, we return [3,1,0,0,0].
There are 2 blocks with two black cells (the ones starting with cell coordinates [0,0] and [0,1]).
The other 2 blocks have starting cell coordinates of [1,0] and [1,1]. They both have 1 black cell.
Therefore, we return [0,2,2,0,0].
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